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1958 Tybee Island mid-air collision
The Tybee Island B-47 crash was an incident on February 5, 1958, in which the United States Air Force lost a Mark 15 nuclear bomb in the waters off Tybee Island near Savannah, Georgia, United States. During a practice exercise, an F-86 fighter plane collided with the B-47 bomber carrying the bomb. To protect the aircrew from a possible detonation in the event of a crash, the bomb was jettisoned. Following several unsuccessful searches, the bomb was presumed lost somewhere in Wassaw Sound off the shores of Tybee Island.
== Midair collision ==
The B-47 bomber was on a simulated combat mission from Homestead Air Force Base in Florida. It was carrying a single bomb. At about 2:00 AM, an F-86 fighter collided with the B-47. The F-86 crashed, after the pilot ejected from the plane. The damaged B-47 remained airborne, plummeting up to while Major Richardson regained flight control.〔Boeing B-47 Stratojet ()〕〔(BBC News ), Missing for 50 years - US nuclear bomb (22 June 2009)〕
The crew requested permission to jettison the bomb, in order to reduce weight and prevent the bomb from exploding during an emergency landing. Permission was granted, and the bomb was jettisoned at while the bomber was traveling at about . The crew did not see an explosion when the bomb struck the sea. They managed to land the B-47 safely at the nearest base, Hunter Air Force Base. The pilot, Colonel Howard Richardson, was awarded the Distinguished Flying Cross after this incident.〔
抄文引用元・出典: フリー百科事典『 ウィキペディア（Wikipedia）』
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